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Calculate pH of - 10^(-3)N HNO(3)...

Calculate pH of -
`10^(-3)N HNO_(3)`

Text Solution

Verified by Experts

Strong acids ionize completely at normal dilutions
`10^(-3)N HNO_(3): HNO_(3) to H^(+)+NO_(3)^(-)`
Conc. before ionisation `10^(-3)" 0 0"`
Conc. after ionisation `"0 "10^(-3)" "10^(-3)`
`therefore [H^(+)]=10^(-3)` mol/litre or eq./litre `(H^(+)" is monovalent")`
`therefore pH=-log [H^(+)]=-log 10^(-3)`
`therefore pH=3`
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