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Calculate pH for - 0.001 N NaOH...

Calculate pH for -
`0.001 N NaOH`

Text Solution

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`0.001 N NaOH`
`NaOH to Na^(+) + OH^(+)`
`10^(-3)N" 0 0"`
`"0 "10^(-3)" "10^(-3)`
`therefore [OH^(-)]=10^(-3)M`
`therefore pOH=-log[OH]^(-)=-log 10^(-3)=3`
`therefore pH=14-pOH =14-3=11`
`therefore pH=11`
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