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The solubility of Mg(OH)(2) in pure wate...

The solubility of `Mg(OH)_(2)` in pure water is `9.57xx10^(-3)`g `litre^(-1)`. Calculate the pH of its saturated solution. (Assume `100%` ionisation)

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Solubility of `Mg(OH)_2` in pure water `=9.47 xx 10^(-3) "g/litre"`
`=(9.57 xx 10^(-3))/(58)" mole litre "=1.65 xx 10^(-4)M`
`Mg(OH_(2)) to Mg^(2+)+2OH^(-`)
`therefore [OH^(-)]=2 xx [Mg(OH)_(2)]`
`=2 xx 1.65 xx 10^(-4) =3.3 xx 10^(-4)`
`therefore pOH=-log [OH^(-)]=3.48`
`therefore pH=14-348=10.52`
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