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Calculate the pH of a solution of given ...

Calculate the pH of a solution of given mixtures,
(0.25 mole of `CH_3COOH+0.35" mole of "CH_3-COONa)` in 500 mL mixture,
`K_a" for "CH_3COOH= 3.6 xx 10^(-4)`

Text Solution

Verified by Experts

`pH =-log K_b+log (["salt"])/(["Acid"])`
`=-log 3.6 xx 10^(-4) +log (0.35//500)/(0.25//500)`
pH =3.5898
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