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Calculate the pH of the resultant mixtur...

Calculate the pH of the resultant mixtures :
10mL of 0.2 M `Ca(OH)_(2)+"25 mL of 0.1 M HCl"`

Text Solution

Verified by Experts

`Meq of Ca(OH)_(2)=10 xx 0.2 xx 2=4`
Meq of HCl `=25 xx 0.1 xx 1=2.5`
`["Meq. "=N xx V_("mL")=M xx "Valance factor "xx V_(Ml)]`
Meq. of `Ca(OH)_(2)" left "=4-2.5=1.5`
`NCa(OH_(2))=(1.5)/(10+25)=4.29 xx 10^(-2)`
`therefore pOH=1.3675 therefore pH=12.6325`
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