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20ml of 0.2 M NaOH is added to 50 ml, of...

`20ml` of `0.2 M NaOH` is added to `50 ml`, of `0.2 M CH_(3)COOH` to give `70 ml`, of the solution. What is the `pH` of the solution? The ionization constant of acetic acid is `2xx10^(-5)`

A

4.522

B

5.568

C

6.522

D

7.568

Text Solution

Verified by Experts

The correct Answer is:
A
The addition of NaOH converts equivalent amount of acetic acid into sodium acetate. Hence, Concen. of acetic acid after the addition of `NaOH =30/70 xx 0.2 M`
Concen. of `CH_2COONa` after the addition of `NaOH =70 20 xx 0.2M` Hense, Using the expression
`pH=pK_(a)+log (["salt"])/(["Acid"])`
`=-log (2 xx 10^(-5)) +log ((20)/(30))`
`=4.699 -0.177=4.522`
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