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How many mole of HCI will be required t...

How many mole of HCI will be required to prepare one litre of buffer solution (containing `NaCN+ HCI`) of `pH 8.5` using `0.01`g formula weight of NaCN ? `K_(HCN)=4.1xx10^(-10))`

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NaCN + HCl is not a buffer but if HCl is in less amount then, it gives a buffer as it produces HCN.
`NaCN+HCl to NaCl+HCN`
Mole added `0.01" a 0 0"`
Mole after reaction (0.01-a)`" 0 a a"`
This is buffer of HCN+NaCN
Let a mole of HCl be used for this purpose
`pH=-log K_(a)+log""(0.01-a)/(a)`
`8.5=-log 4.1 xx 10^(-10) +log""(0.01-a)/(a)`
`therefore a=8.85 xx 10^(-3)` mole of HCl.
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