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Calculate the pOH -pKb for the buffer, ...

Calculate the pOH `-pK_b` for the buffer, 0.20 M `NH_(3), 0.40M NH_(4)Cl, K_(b)" for ammonia "=2xx 10^(-5)`

A

0.5

B

0.6

C

0.3

D

0.75

Text Solution

Verified by Experts

The correct Answer is:
C
`pOH =pK_(b)+log (["Salt"])/(["Base"])`
`pOH -pK_(b)=log""(0.4)/(0.2)=0.30`
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