Home
Class 12
CHEMISTRY
Calculate the pH of an aqueous solution ...

Calculate the pH of an aqueous solution of `1.0M` ammonium formate assuming complete dissociation. `(pK_(a)` of formic acid `= 3.8 and pK_(b)` of ammonia `= 4.8`)

A

3.5

B

4.5

C

5.5

D

6.5

Text Solution

Verified by Experts

The correct Answer is:
D

Ammonium formate =salt of (WA+WB)
`pH =1/2 [pK_(W)+pK_(a)-pK_b]`
`=1/2 [14+3.8 -4.8]=6.5`
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILIBRUIM

    MOTION|Exercise Exercise -1|58 Videos
  • IONIC EQUILIBRUIM

    MOTION|Exercise Exercise -2 (Level -1)|37 Videos
  • HYDROCARBON

    MOTION|Exercise Exercise - 4 (Level-II)|15 Videos
  • ISOMERISM

    MOTION|Exercise Exercise 4|26 Videos

Similar Questions

Explore conceptually related problems

What will be the pH of an aqueous solution of 1.0 M ammonium formate? Given : pK_(a)=3.8 and pK_(b)=4.8

The pH of aqueous solution of ammonium formate is (pK_(a) of HCOOH =3.7 and NH_(3)=4.8)

Calculate the pH of 0.05M sodium acetate solution, if the pK_(a) of acetic acid is 4.74 .

Calculate the pH of a 0.1 M aqueous ammonium cyanide solution. Given pK_a =9.02 and pK_b =4.76