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The solubility of Sr(OH)(2) at 298 K is ...

The solubility of `Sr(OH)_(2)` at `298 K` is `19.23 g L^(-1)` of solution. Calculate the concentrations cf strontium and hydroxyl ions and the `pH` of the solution.

Text Solution

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`Sr(OH)_(2) to Sr^(2+)+2OH^(-)`
`[Sr(OH)_(2)]=(19.23)/(121.62 xx 1)=0.158M)`
`therefore [OH^(-)]=2 xx 0.158 M=0.316M or pOH =0.5003 therefore pH =13.4997`
`[Sr^(2+)]=0.158M`
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