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What should be the concentration of NaA....

What should be the concentration of NaA. If its 50 mL solution is added to 50 mL of 0.2 M HA to have a pH = 4. `K_a " for HA "= 1.0 xx 10^(-5)`.

Text Solution

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Let a be the concentration of NaA. After mixing `M_(NaA)=(a xx 50)/(100)=a/2 and M_(HA)=(0.2 xx 50)/(100)=0.1`
Now, `pH =-log K_(a)+log (["Salt"])/(["Acid"])`
`4=-log (1.0 xx 10^(-5))+log (a//2)/(0.1)`
`therefore a=0.2M`
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