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What is the solubility of AgCl in 0.20 M...

What is the solubility of AgCl in 0.20 M `NH_3` ?
Given : `K_(sp)(AgCl) = 1.7 xx 10^(-10) M^(2), K_(1)=[Ag(NH_(3))^(+)]//[Ag^(+)] [NH_(3)]=2.33 xx 10^(3) M^(-1) and K_(2)=[Ag(NH_(3))_(2)^(+)]//[Ag (NH_(3))^(+) [NH_(3)]=7.14 xx 10^(3) M^(-1)`

A

`6.66 xx 10^(-3)`

B

`9.66 xx 10^(-5)`

C

`9.66 xx 10^(-3)`

D

`6.66 xx 10^(-5)`

Text Solution

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The correct Answer is:
C
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