Home
Class 12
CHEMISTRY
The volume of nitrogen gas at 0^(@)C and...

The volume of nitrogen gas at `0^(@)C` and 1.013 bar required to cover a sample of silica gel with unimolecular layer is `129 cm^(3) g^(–1)` of gel. Calculate the surface area per gram of the gel if each nitrogen molecule occupies `16.2 xx 10^(–20) m^(2)`.

Text Solution

Verified by Experts

`568m^(2)g^(-1)`
`PV=nRT`
`1.013 xx 0.129 = n xx 0.0821 xx 273`
`n=0.00583` mol
Area occupied
`=0.00583 xx 6.023 xx 10^(23) xx 16.2 xx 10^(-20)`
Promotional Banner

Topper's Solved these Questions

  • SURFACE CHEMISTRY

    MOTION|Exercise DISCUSSION QUESTIONS|10 Videos
  • SURFACE CHEMISTRY

    MOTION|Exercise Exercise - 1|52 Videos
  • SOLID STATE

    MOTION|Exercise Exercise - 4 | Level-II|9 Videos
  • THERMOCHEMISTRY

    MOTION|Exercise Exercise - 4 Level-II|8 Videos

Similar Questions

Explore conceptually related problems

The volume of nitrogen gas Um (measured at STP) required to cover a sample of silica get with a mono-molecular layer is 129 cm^(3) g^(-1) of gel. Calculate the surface area per gram of the gel if each nitrogen molecule occupies 16.2 xx 10^(-20) m^(2).

The volume of nitrogen gas Vm (at STP) reqired to cover a sample of silica gel with a monomolecular layer is 129cm^(3)g^(-1) of gel. Calculate the surface area per gram of the gel if each nitrogen molecule occupies 16.23xx10^(-20)m^(2) .

At 1 atm and 273 K the volume of nitrogen gas required to cover a sample of silica gel, assuming Langmuir monolayer adsorption , is found to be 1.30 cm^(3)g^(-1) of the gel. The area occupoied by a nitrogen molecule os 0.16nm^(2) . Find out the no. of surface sites occupied per molecule of H_(2) .

Volume of N_(2) at 1 atm, 273 K required to form a monolayer on the surface of iron catalyst is 8.15ml//gm of the adsorbent. What will be the surface area of the adsorbent per gram if each nitrogen molecule occupies 16 xx 10^(-22)m^(2) ? [Take : N_(A)=6xx10^(23) ]

1.30 cm^(3) of N_(2) gas at STP is adsorbed per gram of silica gel. The area occupied by nitrogen molecule is 0.16 nm^(2) . What is the surface area per gram of silica gel ? (N_(A)=6.023xx10^(23))