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1.30 cm^(3) of N(2) gas at STP is adsorb...

1.30 `cm^(3)` of `N_(2)` gas at STP is adsorbed per gram of silica gel. The area occupied by nitrogen molecule is 0.16 `nm^(2)`. What is the surface area per gram of silica gel ?
`(N_(A)=6.023xx10^(23))`

A

`1.6 m^(2)g^(-1)`

B

`5.568m^(2)g^(-1)`

C

`348m^(2)g^(-1)`

D

`4.42m^(2)g^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Number of `N_(2)` molecules adsorbed per gram of silica gel
`=(1.30xx6xx10^(23))/(22400)=3.48xx10^(9)`
Area of cross-section of molecule `=0.16nm^(2)`
`=1.6xx10^(-19)m^(2)`
Surface area covered per gram of silica gel
`=1.6xx10^(-19)xx3.48 xx 10^(19)=5.568m^(2)`
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