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Plot of log x/m against log p is a strai...

Plot of log `x/m` against log `p` is a straight line inclined at an angle of `45^(@)` . When the pressure is `0.5` atm and Freundlich parameter `k` is `10.0` , the amount of the solute adsorbed per gram of adsorbent will be `(log 5=0.6990)` :

A

1 g

B

2g

C

3g

D

5g

Text Solution

Verified by Experts

The correct Answer is:
D
`log((x)/(m))=log k +(1)/(n) log P`
`(1)/(n)=tan45^(@)=1`
`logk=log10=1`
`(x)/(m)=k(P)^(1//n)=10(0.5)^(1)=5`
When `m=1g, x=5g`
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