The volume of gases `NH_(3), CO_(2) and CH_(4)` adsorbed by one gram of charcoal at 298 K are in

Options

A. `CH_(4) gt CO_(2) gt NH_(3)`
B. `NH_(3) gt CH_(4) gt CO_(2)`
C. `NH_(3) gt CO_(2) gt CH_(4)`
D. `CO_(2) gt NH_(3) gt CH_(4)`

Answer

To determine the order of the volume of gases \( NH_3 \), \( CO_2 \), and \( CH_4 \) adsorbed by one gram of charcoal at 298 K, we need to consider the nature of adsorption and the properties of these gases.

### Step-by-Step Solution:

1. **Understanding Adsorption**: Adsorption is the process where gas molecules adhere to the surface of a solid (in this case, charcoal). The extent of adsorption can depend on several factors, including the nature of the gas, the surface area of the adsorbent, and the temperature.

2. **Nature of Gases**:
- **\( NH_3 \)** (Ammonia): This gas is polar and can form hydrogen bonds. It has a strong interaction with the surface of charcoal due to its polarity.
- **\( CO_2 \)** (Carbon Dioxide): This gas is also polar but less so than ammonia. It can interact with the surface through van der Waals forces and some dipole interactions.
- **\( CH_4 \)** (Methane): This gas is non-polar and has the weakest interactions with the charcoal surface compared to \( NH_3 \) and \( CO_2 \).

3. **Comparing Adsorption Strength**: Based on the nature of the gases:
- \( NH_3 \) will be adsorbed the most due to its ability to form hydrogen bonds and strong polar interactions.
- \( CO_2 \) will be adsorbed next because it has some polar characteristics and can interact with the surface.
- \( CH_4 \) will be adsorbed the least since it is non-polar and has weak van der Waals interactions.

4. **Conclusion**: Therefore, the order of the volume of gases adsorbed by one gram of charcoal at 298 K is:
\[ NH_3 > CO_2 > CH_4 \]