At what temperature will the r.m.s. velocity of oxygen be one and half times of its value at S.T.P. ?

Explanation

`(1)/( 2) mc^(2) = (3)/( 2)kT`
Suppose the temperature required is T' then the velocity will be `(3)/(2) C `
`:. ( 1)/(2) mc'^(2) = ( 3)/( 2) kT'` `:. ( 3//2C)/ ( C ) = sqrt(( T')/( T))` or, `T' = ( 9)/( 4) xx 273 = 614. 25^(@)K`