Calculate the average and total kinetic energyof 0.5 mole of an ideal gas at `0^(@)C`.

Explanation

Average kinetic energy `= ( 3)/( 2) KT = ( 3)/( 2) xx 1.38 xx 10^(-23) xx 273 =5.65 xx 10^(21) J`
Total kinetic energy of n mole of gas `=n xx( 3)/( 2) RT =0.5 xx ( 3)/( 2) xx8.314 xx 273 = 1.70 2 kJ`