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The ratio of rate of diffusion of gases ...

The ratio of rate of diffusion of gases A and B is `1:4` and their molar mass ratio is `2:3`.Calculate the composition of the gas mixture initially effusing out.

Text Solution

Verified by Experts

By Graham's Law `:`
`(r_(A))/( r_(B)) =( P_(A))/( P_(B))sqrt((M_(B))/( M_(A))) rArr (1)/( 4) = ( P_(A))/( P_(B)) sqrt((3)/(2)) rArr (P_(A))/( P_(B)) =( 1)/( 4) sqrt( ( 2)/( 3))`
`rArr ` Mole ratio of gas A and B effusing out `= ( 1)/( 4) sqrt((2 )/( 3))` [ moles `prop ` pressure ]
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