The pressure exerted by `12 g` of an ideal gas at temperature `t^(@)C` in a vessel of volume `V litre` is `1 atm`. When the temperature is increased by `10^(@)C` at the same volume, the pressure increases by `10%`. Calculate the temperature `t` and volume `V`. (Molecular weight of the gas is `120`).

Explanation

Usingn Gas equation `: PV =nRT`
We have, `P xx V = 0.1 xx R xx t ` …..(1) Using (i) and (ii) , we have `: ( t)/( t + 10 ) = ( 1)/( 1.1)`
`rAtt t=100 k ` or `t = -173^(@)C`
Putting the value of t in ( i ) , we get `:`
`rArr 1xx V =0.1 xx0.0821 xx 100 rArr V = 0.82 1 L`