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When 3.2 gm of sulphur is vapourized at ...

When 3.2 gm of sulphur is vapourized at `450^(@)C` and 723 mm pressure, the vapour occupies a volume of 780 m, what is the formula for the sulphur under these conditions?

Text Solution

Verified by Experts

The molecular weight = no. of atoms `xx` atomic mass
So let us find the molecular weight of S from the data given.
`M_(0) = ( g RT)/( PV) = ( 3.2 xx0.0821 xx 723)/((723 xx 760) xx( 780 //1000)) =256`
`rArr` Number of atoms `= ( 256)/( 32) = 8`
Hence, molecular formula of sulphur `= S_(8)`
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