The odour from a gas A takes six seconds to reach a wall from a given point.If the molecular weightof gas A is 46 grams per moles and the molecular weight of gas B is 64 grams per mole. How long will it take for the odour from gas B to reach the same wall from the same point. Approximately -

Options

A. 6 Sec
B. 7 Sec
C. 8 Sec
D. 9 Sec

Answer

B

Explanation

`( r_(A))/( r_(B)) =sqrt((M_(B))/( M_(A))) rArr (r_(A))/( r_(B)) = sqrt(( 64)/( 46)) = 1.18`
Time taken for the odour of B to reach the wall = 1.18 `xx 6 =7.08 sec ~== 7` sec.