If one mole each of a monoatomic and diatomic gases are mixed at low temperature then `C_(p)//C_(v)` ratio for the mixture is :

Options

A. `1.40`
B. `1.428`
C. 1.5
D. 1.33

Answer

C

Explanation

`C_(v) = (((3)/(2) R +( 5)/( 2) R) )/(2) =2R`
`C_(p) =(((5)/(2) R + (7)/( 2)R))/( 2) =3R`
`( C_(p))/( C_(v))= 1.5`