The average speed at temperature `T^(@)C` of `CH_(4)(g)` is `sqrt((28)/(88))xx10^(3)ms^(-1)`. What is the value of T ?

Options

A. `240.55^(@)C`
B. `- 32.45^(@)C`
C. `3000^(@)C`
D. `-24.055^(@)C`

Answer

B

Explanation

`sqrt((8RT)/( pi M))=sqrt(( 28)/( 88)) =sqrt((7)/( 22))`
`( 8 xx 8.314 xx T)/( pi xx 16 xx 10^(-3))= ( 7)/( 22) xx 10^(6)`
`T=( 1000 xx 2)/( 8.314) = 240 . 55K`
`T^(@) C =240.55-273= -32.45^(@)C`