Two vessels connected by a valve of negligible volume. One container (I) has 2.8 g of `N_(2)` at temperature `T_(1) (K)`. The other container (II) is completely evacuated. The container (I) is heated to `T_(2)(K)`while container (II) is maintained at `T_(2)//3(K)`. volume of vessel (I) is half that of vessel (II). If the valve is opened then what is the mass ratio of `N_(2)` is both vessel `(W_(I)//W_(II))`?

Options

A. `1:2`
B. `1:3`
C. `1:6`
D. `3:1`

Answer

C

Explanation

Let x mole of `N_(2)` present into vessel II and P is final pressure of `N_(2)`
`P(2V) =x R( T_(2) //3) ` and `P(V) = ( 0.1 -x ) RT_(2)`
`rArr 2 = ( x)/( 3(0.1-x))`
`rArr x = 0.6 //7` mole
`( 0.6)/( 7) xx 28 rArr 2.4g N_(2)`
IIhas 2.4 g `N_(2)` and I has 0.4 g of `N_(2)`
`( W_(1))/( W_(II)) = (0.4)/( 2.4) rArr 1: 6`