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500 ml of a hydrocarbon gas burnt in exc...

500 ml of a hydrocarbon gas burnt in excess of oxygen yields 2500 ml of `CO_2` and 3 litres of water vapours. All volume being measured at the same temperature and pressure. The formula of the hydrocarbon is :

A

`C_(5) H_(10)`

B

`C_(5) H_(12)`

C

`C_(4) H_(10)`

D

`C_(4)H_(8)`

Text Solution

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The correct Answer is:
B
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MOTION-GASEOUS STATE -EXERCISE -1 (INTRODUCTION & STATE PARAMETERS)
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  3. Most probable speed, average speed and RMS speed are related as -

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  4. The root mean square velocity of an ideal gas in a closed container of...

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  5. The Vander Waal's equation explains the behavior of -

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  6. The correct expression for the van der Waal's equation of state is

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  7. The term that accounts for intermolecular force in van der Waals' equa...

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  8. The critical temperature of a substance is

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  9. Critical temperature of the gas is the temperature

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  10. Molecular attraction and size of the molecules in a gas are not neglig...

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  11. The units of the van der Waals constant a are

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  12. The units of the van der Waal's constant 'b' are

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  13. For H(2) gas, the compressibility factor,Z = PV //n RT is -

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  14. If the Vander Waal's constant of gas A are given as - a ( atm L^(2)...

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  15. The volume of CO2 prodcued by the combination of 40 ml of gaseous ace...

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  16. 500 ml of a hydrocarbon gas burnt in excess of oxygen yields 2500 ml o...

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  17. 15mL of a gaseous hydrocarbon required for complete combustion, 357mL ...

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  18. 7.5 ml of a gaseous hydrocarbon was exploded with 36 ml of O2. On cool...

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  19. A gaseous alkane was exploded with oxygen. The volume of O(2) for comp...

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  20. LPG is a mixture of n-butane and iso-butane. The volume of oxygen need...

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