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The bond dissociation energy of gaseous ...

The bond dissociation energy of gaseous `H_(2), Cl_(2)` and `HCl` are `104, 58` and `103 kcal mol^(-1)` respectively. The enthalpy of formation for `HCl` gas will be

Text Solution

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`H - Cl to H(g) + Cl(g)`
`sum H - Cl = DeltaH_(f) ^(@) H (g) + H_(f)^(@) Cl (g) - Delta_(f)^(@) HCl (g)`
`103 = (1)/(2) sum H - H + (1)/(2) sum Cl - Cl - Delta H_(f)^(@) HCl (g)`
`103 = (1)/(2) xx 104 + (1)/(2) xx 58 - Delta H_(f)^(@) HCl (g)`
`implies DeltaH_(f)^(@) HCl (g) = -22 ` kcal/mol.
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