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Using the bond enthalpy data given below...

Using the bond enthalpy data given below, calculate the enthalpy of formation of acetone (g).
Bond enegry `C-H = 413.4 kJ mol^(-1)`,
Bond enegry `C-C = 347.0 kJ mol^(-1)`,
Bond enegry `C=O = 728.0 kJ mol^(-1)`,
Bond enegry `O=O = 495.0 kJ mol^(-1)`,
Bond enegry `H-H = 435.8 kJ mol^(-1)`,
`Delta_("sub")H^(Theta)C(s) = 718.4 kJ mol^(-1)`

Text Solution

Verified by Experts

`CH_(3)-overset(O)overset(||)(C)-CH_(3) to 3 C(g) + 6 H(g) + O(g) 6 sum C - H + sum C = O + 2 sum C - C = 3 Delta H_(f)^(@) C(g) + 6 DeltaH_(f)^(@) H (g) + Delta H_(f)^(@) O(g) - Delta H_(f)^(@) (CH_(3) - overset(O)overset(||)(C)- CH_(3)) 6 xx 413. 4 + 728 + 2 xx 347 = 3 xx 718.4 + (6)/(2) xx 435. 8 + (1)/(2) xx 495.0 - H_(f)^(@) (CH_(3) - overset(O)overset(||)(C)-CH_(3))`
`implies Delta H_(f)^(@) (CH_(3) - overset(O)overset(||) - CH_(3)) = -192 . 3 kJ mol^(-1)`
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