If `ABCDEF` is a regular hexagon with `vec(AB) = veca` and `vec(BC)= vecb,` then `vec(CE)` equals

If ABCDEF is a regular hexagon with vec(AB) = vec(a) ,vec(BC ) = vec(b) then vec(CE) equals :

If ABCDEF is a regular hexagon with vec AB=vec a and vec BC=vec b, then vec CE equals

If ABCDEF is a regular hexagon then vec AD + vec EB + vec FC =

ABCDEF is a regular hexagon. If vec(AB) = vec(a) and vec(BC) = vec(b), " find " vec(CD), vec(DE), vec(EF) and vec(FA) in terms of vec(a) and vec(b)

Assertion ABCDEF is a regular hexagon and vec(AB)=veca,vec(BC)=vecb and vec(CD)=vecc, then vec(EA) is equal to -(vecb+vecc) , Reason: vec(AE)=vec(BD)=vec(BC)+vec(CD) (A) Both A and R are true and R is the correct explanation of A (B) Both A and R are true R is not te correct explanation of A (C) A is true but R is false. (D) A is false but R is true.

Assertion ABCDEF is a regular hexagon and vec(AB)=veca,vec(BC)=vecb and vec(CD)=vecc, then vec(EA) is equal to -(vecb+vecc) , Reason: vec(AE)=vec(BD)=vec(BC)+vec(CD) (A) Both A and R are true and R is the correct explanation of A (B) Both A and R are true R is not te correct explanation of A (C) A is true but R is false. (D) A is false but R is true.

If ABCDEF is a regualr hexagon, then vec(AC) + vec(AD) + vec(EA) + vec(FA)=

If ABCDEF is a regular hexagon then vec(AD)+vec(EB)+vec(FC) equals :

If ABCDEF is a regular hexagon then vec(AD)+vec(EB)+vec(FC) equals :