Find the smallest integral value of `x` satisfying `(x-2)^(x^2-6x+8))>1`

Explanation

`(x-2)^(x^2-6x+8)`

1)`x-2<1`

`x^2-6x+8>0`

`x^2-4x-2x+8>0`

`(x-4)(x-2)>0`

`x in (-oo.2)(4,oo)`

`x in(4,oo)`

2)`x-2<1`

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