For `x >2, if log_(1/7)(3^x+2x-5)=x(1-log_7 21)` then x=

If log_(2)(3^(2x-2)+7)=2+log_(2)(3^(x-1)+1) then x=

If log_3 2+log_3 (2^x-7/2)=2log_3 (2^x-5) then x=

If log_(2)x + log_(2)x=7 , then =

Solve for x : (i) log_(10) (x - 10) = 1 (ii) log (x^(2) - 21) = 2 (iii) log(x - 2) + log(x + 2) = log 5 (iv) log(x + 5) + log(x - 5) = 4 log 2 + 2 log 3

If x satisfies log_2(9^(x-1)+7)=2+log_2(3^(x-1)+1) , then

If x satisfies log_2(9^(x-1)+7)=2+log_2(3^(x-1)+1) , then

If x satisfies log_2(9^(x-1)+7)=2+log_2(3^(x-1)+1) , then