" If "n=1983!" then value of expression "(1)/(log_(7)n)+(1)/(log_(2)n)+(1)/(16g_(4)n)=(1)/(log_(100)14)" is carns to "

The value of (1)/(log_(3)n)+(1)/(log_(4)n) + (1)/(log_(5)n) + ... + (1)/(log_(8)n) is ______.

(1)/(log_(2)(n))+(1)/(log_(3)(n))+(1)/(log_(4)(n))+....+(1)/(log_(43)(n))

(1)/(log_(2)(n))+(1)/(log_(3)(n))+(1)/(log_(4)(n))+....+(1)/(log_(43)(n))

What is the value of (1)/(log_(2)n)+(1)/(log_(3)n)+ . . .+(1)/(log_(40)n) ?

What is (1)/(log_(2)N)+(1)/(log_(3)N)+(1)/(log_(4)N)+....+(1)/(log_(100)N) " equal to "(Nne1) ?

In n = 10!, then what is the value of the following? (1)/(log_(2)n) +(1)/(log_(3)n) +(1)/(log_(4)n)+…..+ (1)/(log_(10)n)

If n>1, then prove that(1)/(log_(2)n)+(1)/(log_(3)n)+...+(1)/(log_(53)n)=(1)/(log_(53)n)