Suppose `x , y ,z=0` and are not equal to 1 and `logx+logy+logz=0.` Find the value of `1/(x^(logy))+1/(^(logz))1/(y^(logz))+1/(^(logx))1/(z^(logx))+1/(^(logy))`

Suppose x;y;z>0 and are not equal to 1 and log x+log y+log z=0. Find the value of x(1)/(log y)+(1)/(log z)xx y^((1)/(log z)+(1)/(log x))xx(1)/(log x)+(1)/(log y) (base 10)

Find the value of int dx/(x(logx -1)(logx + 1))

The value of x^((logy-logz))xx y^((logz - logx)) xx z^((log x- logy)) is equal to

int(logx)/(x(1+logx)(2+logx))dx=

∫ (1)/(x.logx.(2+logx))

int_(0)^(e^(2)){(1)/((logx))-(1)/((logx)^(2))}dx

If x, y and z are in G.P, then show that logx, logy, logz are in A.P.