If `A, B` and are collinear find `lambda` non-collinear such that `vecc=(lambda-2)veca+vecb` and `vecd=(2lambda+1)veca-vecb,vecc` and `vecd` are collinear find `lambda`

The vectors bara and barb are non-collinear The value of x for which the vectors vecc=(x-2)veca+vecb and vecd=(2x+1)veca-vecb are collinear, is

The vectors bara and barb are non-collinear The value of x for which the vectors vecc=(x-2)veca+vecb and vecd=(2x+1)veca-vecb are collinear, is

For what value of lambda , the vectors (lambda-2)veca+vecb and (4lambda-2)veca+3vecb are collinear

The vectors veca and vecb are non collinear. Find for what value of x the vectors vecc=(x-2)veca+vecb and vecd=(2x+1) veca-vecb are collinear.?

The vectors veca and vecb are non collinear. Find for what value of x the vectors vecc=(x-2)veca+vecb and vecd=(2x+1) veca-vecb are collinear.?

The vectors veca and vecb are non collinear. Find for what value of x the vectors vecc=(x-2)veca+vecb and vecd=(2x+1) veca-vecb are collinear.?

Prove that [lambda veca +mu vecb" "vecc" "vecd]=lambda [veca" "vecc" "vecd]+mu[vecb" "vecc" "vecd] .

If veca , vecb , vecc are non-coplanar vectors and lambda is a real number then [ lambda(veca+vecb) lambda^2vecb lambdavecc ] = [ veca vecb+vecc vecb ] for:

If veca and vecb are non zero, non collinear vectors and veca_(1)=lambda veca+3 vecb, vecb_(1)=2veca+lambda vecb, vec c_(1)=veca+vecb . Find the sum of all possible real values of lambda so that points A_(1), B_(1), C_(1) whose position vectors are veca_(1), vecb_(1), vec c_(1) respectively are collinear is equal to.