" (6) the Area bounded by "|x|+|y|=1

Using integration, prove that the area bounded by : |x|+|y|=1 is 2 sq.units.

The area bounded by curve |x|+|y|>=1 and x^(2)+y^(2) =0 is

The area bounded by |x|+|y|=1 and y ge x^(2) in the first quadrant is a-(a^(2))/(2)-(a^(3))/(3) sq. units, then the value of (2a+1)^(2) is equal to

The area bounded by curve |x|+|y| >= 1 and x^2+y^2 = 0 is

The area bounded the curve |x|+|y|=1 is

The area bounded by y-1 = |x|, y = 0 and |x| = (1)/(2) will be :

The area bounded by |x| =1-y ^(2) and |x| +|y| =1 is:

The area bounded by |x| =1-y ^(2) and |x| +|y| =1 is:

The area bounded by the curve |x|+|y|=1 and axis of x, is given by