[(2)/(x)+(3)/(y)=22,(5)/(x)-(4)/(y)=9],[x,y!=0]

(3) / (x) - (1) / (y) + 9 = 0 (2) / (x) + (3) / (y) = 5, (! = 0, y! = 0)

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

(x-4)(x-3)=(x-6)(x-5) (y-9)(y-3)= (y-4)(y-3)

If x^(3)-2x^(2)y^(2)+5x+y-5=0 and y(1)=1, then (a y'(1)=(4)/(3)(b)y'(1)=-(4)/(3)(c)y''(1)=-8(22)/(27) (d) y'(1)=(2)/(3)

Solve for x and y in the following question : 2/(x+2y)+1/(2x-y)+5/9=0, 9/(x+2y)+6/(2x-y)+4=0

{:("Column" A ,, "Column" B), ((3x^(2) - 5)- (2x^(2) - 5 + y^(2)) ,, (a) x^(2) + xy + y^(2)) , (9x^(2) - 16y^(2) ,, (b) 2) , ((x^(3) - y^(3))/(x-y) ,, (c) (9x + 16y) (9x - 16y)) , ("The degree of " (x + 2) (x+3) ,, (d) x^(2) - y^(2)) , (,, (e) 1) , (,, (f) (3x + 4y) (3x - 4y)):}

The circles whose equations are x^(2)+y^(2)+10x-2y+22=0 and x^(2)+y^(2)+2x-8y+8=0 touch each other. The circle which touch both circles at, the point of contact and passing through (0,0) is, 1) 9(x^(2)+y^(2))-15x-20y=0, 2) 5(x^(2)+y^(2))-18x-80y=0 3) 7(x^(2)+y^(2))-18x-80y=0, 4) x^(2)+y^(2)-9x-40y=0 ]]

((x^(5y-3)xx x^(3-2y))/(x^(4y-6)xx x^(2y-9)))^(-4/3)= ______

8x+5y=9 3x+2y=4