" If "|[a+x,a-x,a-x],[a-x,a+x,a-x],[a-x,a-x,a+x]|=theta" then "x" is "

If |(a+x, a-x, a-x),(a-x,a+x,a-x),(a-x,a-x,a+x)|=0 then

If |(a +x,a -x,a -x),(a -x,a +x,a -x),(a -x,a -x,a +x)| = 0 , then x is equal to

Using properties of determinants, solve for x:|[a+x, a-x, a-x],[ a-x, a+x, a-x],[ a-x, a-x, a+x]|=0

Using properties of determinants, solve for x:|[a+x, a-x, a-x], [a-x, a+x, a-x], [a-x, a-x ,a+x]|=0

Using properties of determinants, solve for x:|[a+x, a-x, a-x],[ a-x, a+x, a-x],[ a-x, a-x, a+x]|=0

Solve for x : |(a+x,a-x,a-x),(a-x,a+x,a-x),(a-x,a-x,a+x)|=0

Solve for x: |[x,c+x,b+x],[c+x,x,a+x],[b+x,a+x,x]|=0

|[x+4,x,x] , [x,x+4,x] , [x,x,x+4]|=16(3x+4)

|[x+3,x,x] , [x,x+3,x] , [x,x,x+3]|=27(x+1)

Using the properties of determinants, solve the following for x |{:(a+x,a-x,a-x),(a-x,a+x,a-x),(a-x,a-x,a+x):}|=0