If the point `(0,0),(2,0),(3,1),(1,2),(3,3),(4,3) and (2,4)` at most how many can be on a circle? Find the equation of this circle also.

The foot of the normal from the point (1,2) to a circle is (3,4) and a diameter of the circle has the equation 2x+y+5=0 ,then the equation of the circle is

Show that the points (2, 0), (5, -3), (2, -6) and (-1, -3) are concyclic, find the equation of the circle on which the points lie and the coordinates of the centre of the circle.

The extremities of a diameter of a circle are the points (4, -2) and (1, -3), find the equation of the circle. Also find the equation of that diameter of this circle which passes through the origin.

A foot of the normal from the point (4, 3) to a circle is (2, 1) and a diameter of the circle has the equation 2x -y -2 =0 . Then the equation of the circle is:

If (3,-2) is the centre of a circle and 4x+3y +19 =0 is a tangent to the circle , then the equation of the circle is

A circle passes through the points (-3, 4), (1, 0) and its centre lies on the x-axis. Find the equation of the circle.

If the circle x^(2)+y^(2)+2x+3y+1=0 cuts x^(2)+y^(2)+4x+3y+2=0 at A and B ,then find the equation of the circle on AB as diameter.

Four points on a circle are (0,1), (1,0), (0,0), (2k, 3k) find k: