m, n are natural numbers. The number of pairs (m, n) for which `m^2+n^2+2mn-2015m-2015n-2016=0` is

If m and n are natural numbers, than root(m)(n) is

Number of ordered pairs of integers (n,m) for which n^(2)-m^(2)=14 is

If m, n are natural numbers, for what values of m, does 2^(n)times5^(m) ends in 5?

Number of ordered pairs of intergers {n,m} for which n^(2)-m^(2)=14 is

Number of ordered pairs of intergers {n,m} for which n^(2)-m^(2)=14 is

If m and n are two distinct numbers such that m >n, then prove that m^2-n^2 ,2mn and m^2+n^2 is a Pythagorean triplet.

If m^2-n^2= 7 , where m, n epsilon Z , then number of ordered pairs (m,n) is

Prove that there exist no natural numbers, m and n such that m^(2)=n^(2)+2002.

Prove that there exist no natural numbers, m and n such that m^(2)=n^(2)+2002.