Perpendiculars are drawn from the angles `A, B and C` of an acute-angled triangle onthe opposite sides, and produced to meet the circumscribing circle. If these produced parts are `alpha., beta, gamma,` respectively, then show that, then show that `a/alpha+b/beta+c/gamma=2(tanA+tanB+tanC).`

Perpendiculars are drawn from the angles A,B and C of an acute-angled triangle onthe opposite sides,and produced to meet the circumscribing circle.If these produced parts are alpha.,beta,gamma, respectively,then show that, then show that then show that (a)/(alpha)+(b)/(beta)+(c)/(gamma)=2(tan A+tan B+tan C)

If alpha,beta ,gamma are direction angles of a line , then cos 2alpha + cos 2beta + cos 2 gamma =

If alpha,beta,gamma are acute angle such that cos alpha=tan beta,cos beta=tan gamma and cos gamma=tan alpha then

If direction angles of a line are alpha, beta, gamma such that alpha+beta=90^(@) , then (cos alpha+cos beta+cos gamma)^(2)=

A line makes angles alpha, beta, gamma with X, Y, Z axes respectively. If alpha=beta and gamma=45^(@) , then alpha+beta+gamma=

If a line makes angle alpha, beta and gamma with the coordinate axes respectively, then cos2alpha+cos 2 beta+cos 2gamma=

If a vector makes angle alpha,beta,gamma with ox,or and OZ respectively,then write the value of sin^(2)alpha+sin^(2)beta+sin^(2)gamma

If a line makes angle alpha, beta and gamma with the axes respectively then sin^(2)alpha+sin^(2)beta+sin^(2)gamma=

If a right angle be divided into three parts alpha,beta and gamma, prove that cot alpha=(tan beta+tan gamma)/(1-tan beta tan gamma)

If a right angle be divided into three parts alpha,beta and gamma, prove that cot alpha=(tan beta+tan gamma)/(1-tan beta tan gamma)