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" (ii) "2y^(3)-5y^(2)-19y+42...

" (ii) "2y^(3)-5y^(2)-19y+42

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y^(3)-2y^(2)-29y-42

The factors of 2y^3 - 5y^2 - 19y + 42 are :

Subtract : 5y^(4) - 3y^(3) + 2y^(2) + y - 1 from 4y^(4) - 2y^(3) - 6y^(2) - y + 5

2y ^ (4) + y ^ (3) -14y ^ (2) -19y-6

If p(y)=y^(3)-5y^(2)+5y+10 , then find p(2) +p(-2).

If p(y)=y^(3)-5y^(2)+5y+10 , then find p(2) +p(-2).

((y^(3)-3y^(2)+5y-1)/(y-1))

Divide 36x^(2)y^(5)+42xy^(3)-24x^(3)y^(2)-12y^(5) by -6y^(2) .

Divide : 36x^(2)y^(2) + 42 xy^(3) - 24 x^(3)y^(2) - 12 y^(5) by - 6y^(2)