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If alpha is a root of 25"cos"^(2) theta+...

If `alpha` is a root of `25"cos"^(2) theta+ 5"cos" theta-12 = 0, (pi)/(2) lt alpha lt pi, " then sin"2 alpha` is equal to

A

`(24)/(25)`

B

`-(24)/(25)`

C

`(13)/(18)`

D

`-(13)/(18)`

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The correct Answer is:
B
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