"cos"(2001)pi+"cot"(2001) pi/2+sec(2001)...

`"cos"(2001)pi+"cot"(2001)` `pi/2+sec(2001)pi/3+tan(2001)pi/4+cos e c(2001)pi/6` equal to 0 (b) 1 (c) `-2` (d) not defined

A

0

B

1

C

-2

D

Not defined

Verified by Experts

The correct Answer is:

C

Similar Questions

Explore conceptually related problems

cos(2001)pi+cot(2001)(pi)/(2)+sec(2001)(pi)/(3)+tan(2001)(pi)/(4)+csc(2001)(pi)/(6) equal to 0(b)1(c)-2(d) not defined

cos(2001)?+cot(2001)2+sec(2001)3+tan(2001)4+csc(2001)? equals to (A)0 (B) 1 (C) 2 (D) not defined

sin^(-1)(0) is equal to : (a) 0 (b) pi/6 (c) pi/2 (d) pi/3

The value of 32cot^(2) (pi/4)-8sec^(2)(pi/3)+ 8cos^(3)(pi/6) is equal to

2(2.001)^(3)+7(2.001)+1~~…

cot^2 pi/6 +cose c (5pi)/6 +3tan^2 pi/6=6

tan((pi)/(4)+(1)/(2)cos^(-1)x)+tan((pi)/(4)-(1)/(2)cos^(-1)x),x!=0 is equal to x( b) 2x( c) (2)/(x) (d) none of these

int_(-(pi)/(2))^((pi)/(2))(e^(|sin x|)cos x)/(1+e^(tan x))dx is equal to (a) e+1 (b) 1-(pi)/(2)e(c)e-1(d) none of these