If sin[(pi)/(4)cottheta] = cos[(pi)/(4)t...

If `sin[(pi)/(4)cottheta] = cos[(pi)/(4)tantheta]` then `theta` can be :

A

`npi+(pi)/(2)`

B

`npi +(pi)/(4)`

C

`npi -(pi)/(4)`

D

`npi +(pi)/(3)`

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The correct Answer is:

B

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