If `za n dw` are two complex number such that `|z w|=1a n da rg(z)-a rg(w)=pi/2` , then show that ` z w=-idot`

If z and w are two complex number such that |zw|=1 and arg(z)arg(w)=(pi)/(2), then show that bar(z)w=-i

Let Z and w be two complex number such that |zw|=1 and arg(z)-arg(w)=pi/2 then

If z and w are two non - zero complex numbers such that |zw|=1 and arg(z)-arg(w)=(pi)/(2), then the value of 5ibarzw is equal to

Let zandw be two nonzero complex numbers such that |z|=|w| andarg (z)+arg(w)=pi Then prove that z=-bar(w) .

Let z and w be two complex numbers such that |Z|<=1,|w|<=1 and |z+iw|=|z-ibar(w)|=2

If Z and omega are two complex numbers such that |zomega|=1andarg(z)-arg(omega)=(3pi)/(2) , then arg ((1-2bar(z)omega)/(1+3bar(z)omega)) is : (Here arg(z) denotes the principal argument of complex number z)

Let a complex number be w=1-sqrt3 I, Let another complex number z be such that |z w|=1 and arg(z)-arg (w) =pi/2 . Then the area of the triangle with vertices origin, z and w is equal to :

Let z and w be two non-zero complex number such that |z|=|w| and arg (z)+arg(w)=pi then z equals.w(b)-w (c) w(d)-w

Let z and w are two non zero complex number such that |z|=|w|, and Arg(z)+Arg(w)=pi then (a) z=w( b) z=bar(w)(c)bar(z)=bar(w)(d)bar(z)=-bar(w)