If |z(1)|=|z(2)| and arg (z(1))+"arg"(z(...

If `|z_(1)|=|z_(2)|` and arg `(z_(1))+"arg"(z_(2))=0`, then

A

`z_(1) = -z_(2)`

B

`z_(1) = overline(z)_(2) `

C

`z_(1)z_(2) = 1`

D

None of these

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The correct Answer is:

B

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