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If z=x+iy and omega=(1-iz)/(z-i), then |...

If `z=x+iy` and `omega=(1-iz)/(z-i)`, then `|omega|=1` implies that in the complex plane

A

z lies on imaginary axis

B

z lies on real axis

C

z lies on unit circle

D

None of these

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The correct Answer is:
B
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