If z^(3)+(3+2i)z+(-1+ia)=0, " where " i=...

If `z^(3)+(3+2i)z+(-1+ia)=0, " where " i=sqrt(-1)`, has one real root, the value of a lies in the interval (a `in` R)

A

`(-2,1)`

B

`(-1,0)`

C

`(0,1)`

D

`(-2,3)`

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The correct Answer is:

A, B, D

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