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The line y=mx+c cuts the circle x^2 + y^...

The line `y=mx+c` cuts the circle `x^2 + y^2 = a^2` at two distinct points A and B. Equation of the circle having minimum radius that can be drawn through the points A and B is:

A

`( 1+ m^(2)) (x^(2) + y^(2) -a^(2)) + 2c ( y -mx- c) = 0`

B

`( 1+ m^(2)) (x^(2) + y^(2) -a^(2)) + c ( y -mx- c) = 0`

C

`( 1+ m^(2)) (x^(2) + y^(2) -a^(2)) -2 c ( y -mx- c) = 0`

D

`( 1+ m^(2)) (x^(2) + y^(2) -a^(2)) - c ( y -mx- c) = 0`

Text Solution

Verified by Experts

The correct Answer is:
c
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