The sides of a square are x =4, x = 7, y...

The sides of a square are `x =4, x = 7, y =1 ` and `y = 4 ` . The equation of the circumcircle of the square is `:`

A

`x^(2) +y^(2)+11x =4y +17=0`

B

`x^(2) +y^(2) +7x- 6y + 18 =0`

C

` x^(2) +y^(2) -11x -3y +30=0`

D

` x^(2) + y^(2) -11x - 5y +32 =0`

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The correct Answer is:

D

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